4[1z+3(1z-1)]=36

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Solution for 4[1z+3(1z-1)]=36 equation:


Simplifying
4[1z + 3(1z + -1)] = 36

Reorder the terms:
4[1z + 3(-1 + 1z)] = 36
4[1z + (-1 * 3 + 1z * 3)] = 36
4[1z + (-3 + 3z)] = 36

Reorder the terms:
4[-3 + 1z + 3z] = 36

Combine like terms: 1z + 3z = 4z
4[-3 + 4z] = 36
[-3 * 4 + 4z * 4] = 36
[-12 + 16z] = 36

Solving
-12 + 16z = 36

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 16z = 36 + 12

Combine like terms: -12 + 12 = 0
0 + 16z = 36 + 12
16z = 36 + 12

Combine like terms: 36 + 12 = 48
16z = 48

Divide each side by '16'.
z = 3

Simplifying
z = 3

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